-0,06x^2+2,1x^2-36=0

Solution for -0,06x^2+2,1x^2-36=0 equation:

-0.06x^2+2.1x^2-36=0

We add all the numbers together, and all the variables

2.04x^2-36=0

a = 2.04; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·2.04·(-36)
Δ = 293.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{293.76}}{2*2.04}=\frac{0-\sqrt{293.76}}{4.08}
=-\frac{\sqrt{}}{4.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{293.76}}{2*2.04}=\frac{0+\sqrt{293.76}}{4.08}
=\frac{\sqrt{}}{4.08}
$